Formula 8

\begin{array}{l} F_{T, 1, Rd} = \frac{4 \cdot M_{pl, 1, Rd}}{m} \\ where \\ M_{pl, 1, Rd} = \frac{0.25 \cdot l_{eff, 1} \cdot t_{f} ² \cdot f_{y}}{γ_{M 0}} \\ m = 39.8 mm for the outer bolt row \\ m = 62.6 mm for the inner bolt row \\ M_{pl, 1, Rd} = \frac{0.25 \cdot 15.0 \cdot 2.52 \cdot 23.5}{1.0} = 550.78 kNcm for the outer bolt row \\ M_{pl, 1, Rd} = \frac{0.25 \cdot 39.33 \cdot 2.52 \cdot 23.5}{1.0} = 1, 444.15 kNcm for the inner bolt row \\ F_{T, 1, Rd} = \frac{4 \cdot 550.78}{3.98} = 553.55 kN for the outer bolt row \\ F_{T, 1, Rd} = \frac{4 \cdot 1, 444.15}{6.26} = 922.78 kN for the inner bolt row \end{array}

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