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Sonja von Bloh, M.Sc.
2020-11-20

Load Distribution on Members for Angular Axis Method

How is the load distributed to the members in the angular axis method if the members are excluded from the load application?

Answer:

An area load of 1 kN/m² delimited by Node 1 to Node 4 is only applied to Member 3 (Image 01).

Surface Load
1 Surface Load

The entries carried out in the load generator are shown in Image 02. There is no correction of the distribution according to the moment equilibrium (Image 03).

Settings for Converting Surface Loads to Member Loads
2 Settings for Converting Surface Loads to Member Loads

Settings for Load Generation via Plane
3 Settings for Load Generation via Plane

The generated member load is shown in Image 04. This is calculated as follows:

q = 1.00 kN/m2
h1 = 4.00 m
h2 = 6.00 m
btot = 12.00 m
α =arctan h2 - h1btot = arctan 6.000 - 4.00012.000 = 9.46°
b1 = tan (α) ⋅ h1 = tan (9.46°) ⋅ 4.000 = 0.667 m
l1 = b12 + h12 = 0.6672 + 4.0002 = 4.055 m
l2 = cos (α) ⋅ h2 = cos (9.46°) ⋅ 6.000 = 5.918 m
AR = b1 · h12= 0.667 · 4.0002 = 1.335 m2
ltot = btot2 + h2-h12 = 12.0002 + 6.000-4.0002 = 12.166 m

q

Lastgröße Flächenlast

AR

Restfläche (im Bild 4 rot markiert)

qc

konstanter Lastanteil auf belasteten Stab

q2

Stablast Knoten 2

q5

Stablast Knoten 5

q4

Stablast Knoten 4
Calculation of Member Load

Generated Member Load from Surface Load
4 Generated Member Load from Surface Load

Author

Ms. von Bloh provides technical support for our customers and is responsible for the development of the SHAPE‑THIN program as well as steel and aluminum structures.

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