2024-11-01

Calculation of Member Load

q = 1.00 kN / m^{2}

h_{1} = 4.00 m

h_{2} = 6.00 m

b_{tot} = 12.00 m

α = \arctan (\frac{h_{2} - h_{1}}{b_{tot}}) = \arctan (\frac{6.000 - 4.000}{12.000}) = 9.46 °

b_{1} = \tan (α) \cdot h_{1} = \tan (9.46 °) \cdot 4.000 = 0.667 m

l_{1} = \sqrt{b_{1}^{2} + h_{1}^{2}} = \sqrt{0 . 667^{2} + 4 . 000^{2}} = 4.055 m

l_{2} = \cos (α) \cdot h_{2} = \cos (9.46 °) \cdot 6.000 = 5.918 m

A_{R} = \frac{b_{1} \cdot h_{1}}{2} = \frac{0.667 \cdot 4.000}{2} = 1.335 m^{2}

l_{tot} = \sqrt{b_{tot}^{2} + {(h_{2} - h_{1})}^{2}} = \sqrt{12 . 000^{2} + {(6.000 - 4.000)}^{2}} = 12.166 m

q	Area load
A_R	Remaining area (marked in red in Image 04)
q_c	Constant load component on the loaded member
q₂	Member load Node 2
q₅	Member load Node 5
q₄	Member load Node 4

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