In Eurocode 7, there are three design approaches for determining the ground failure resistance.
- Approach 1
- Approach 2
- Approach 3
In this article, the approaches are compared on the model of a foundation plate with a column. The differences between the individual approaches lies in the partial safety factors that affect various influencing values. These include the actions or loading, soil parameters, and resistances. It is important to mention that these reductions or increases sometimes occur in the approaches in combination. Furthermore, the German National Annex describes special rules for the application of Approach 2, which is also known as Design Approach 2* or 2+. In the following text and in RFEM 6, the term 2* is used for this approach.
System of Foundation Plate with Column
Foundation plate
- Length: wx = 2.50 m
- Width: wy = 2,50 m
- Thickness: t = 1.00 m
- Embedment depth: D = 1.00 m
- Self-weight Gp,k = 156.25 kN with γ = 25 kN/m³
Column
- Length: cx = 0.50 m
- Width: cy = 0.50 m
- Height: h = 4.00 m
- Self-weight: Gc,k = 25 kN with γ = 25 kN/m³
Ground Parameters
- Friction angle: φ'd = 32°
- Shear parameter for cohesion: c'k = 15 kN/m²
- Density of soil next to the foundation plate: γ1.k 20 kN/m³
- Bulk density of soil below the foundation slab: γ2,k = 20 kN/m³
Load Case 1 – Permanent Loads
- Vertical: VG,z,k = 975 kN
Including the self-weight of the column Gc,k = 25 kN and the foundation Gp,k = 156.25 kN, the sum of the permanent vertical loads is VG,k,tot = 156.25 kN + 25 kN + 975 kN = 1,156.25 kN. The self-weight of the foundation is automatically taken into account with the self-weight of the structure as long as the "Active self-weight" check box is selected. If the self-weight is to be entered manually, it is necessary to define additional loads for the foundation.
Load Case 2 – Variable Loads
- Vertical: VQ,z,k = 1,000 kN
- Horizontal: HQ,x,k = 190 kN
Partial Safety Factors
The following table shows the partial safety factors according to EN 1997‑1, A.3.
Actions A | Symbol | A1 | A2 | |
Permanent loads | γG | 1.35 | 1.00 | |
Variable loads | γQ | 1.50 | 1.30 | |
Soil Parameters (Material M) | Symbol | M1 | M2 | |
Effective shear angles | γ'φ | 1.00 | 1.25 | |
Effective cohesion | γ'c | 1.00 | 1.25 | |
Specific Weight | γγ | 1.00 | 1.00 | |
Resistance R | Symbol | R1 | R2 | R3 |
Ground Failure | γR;v | 1.00 | 1.40 | 1.00 |
Sliding | γR;h | 1.00 | 1.40 | 1.00 |
Approach 1
This design approach uses two different sets of partial safety factors.
In the first combination 1-1, the partial safety factors A1, M1, and R1 are used, with A1 (γG = 1.35; γQ = 1.5) increasing the unfavorable actions on the foundation, M1 (γ'φ = γ'c = γγ = 1.00) not reducing the soil parameters, and R1 (γR;v = γR;h = 1.00) not reducing the resistances.
In the second combination 1-2, A2, M2, and R1 are used, with A2 (γG = 1.00; γQ = 1.30) increasing the actions less than A1, and M2 (γ'φ = γ 'c = 1.25; γ γγ = 1.00) reducing the soil parameters by reducing the soil resistance to ground failure.
For the design, the calculation has to be performed with both sets of partial safety factors, and the set with the higher ratio is governing.
Approach 1 (Combination 1-1) According to EN 1997-1, 2.4.7.3.4.2
Calculation of Ground Failure Resistance
Eccentricity ex of Effective Vertical Load in x-Direction
The design shear force with additional foundation loads Vz,+add as well as the value of the resulting design bending moment My,+add in the foundation base center are required to determine the eccentricity of effective vertical loads.
Vz,+add,d = γG ⋅ VG,k + γQ ⋅ VQ,k = 1.35 ⋅ 1,156.25 kN + 1.5 ⋅ 1,000 kN = 3,060.94 kN
HQ,x,d = γQ ⋅ HQ,x,k = 1.50 ⋅ 190 kN = 285 kN
My,+add,d = (t + h) ⋅ HQ,x,d = (1.00 m + 4.00 m) ⋅ 285 kN = 1,425 kNm
ex = -My,+add,d / Vz,+add,d = -1,425 kNm / 3,060.94 kN = -0.466 m
Effective Foundation Length, Width, and Base
The eccentric loading reduces the allowable foundation base.
wx - 2 ⋅ |ex| = 2,50 m - 2 ⋅ 0,466 m = 1,569 m
wy - 2 ⋅ |ey| = 2.50 m - 2 ⋅ 0.000 m = 2.500 m
Effective length: L' = max(wx - 2 ⋅ |ex|; wy - 2 ⋅ |ey|) = 2.500 m
Effective width: B' = min(wx - 2 ⋅ |ex|; wy - 2 ⋅ |ey|) = 1.569 m
Effective area: A' = L' ⋅ B' = 2.500 m ⋅ 1.569 m = 3.922 m²
Soil Parameters to Use
Friction angle: φ'd = arctan(tan(φ'k ) / γ'φ ) = arctan(tan(32°) / 1.00) = 32°
Shear parameter for cohesion: c'd = c'k / γ'c = 15 kN/m² / 1.00 = 15 kN/m²
Bulk density: γ1d = γ2d = γ1k / γγ = γ2k / γγ = 20 kN/m³ / 1.00 = 20 kN/m³
The friction angle φ' describes the angle at which the shear strength of a soil is reached by friction between the soil components. In contrast, cohesion c' refers to the ratio of the shear strength that results from internal binding forces between the soil components – regardless of the stress applied. Both parameters play a central role in determining the shear strength of a soil under various loading conditions. The weight of the soil next to the foundation slab is denoted by γ1d, the weight of the soil below the foundation slab by γ2d.
Bearing Capacity Coefficients
Nq = eπ ⋅ tan(φ‘d) ⋅ tan²(45°+φ‘d / 2) = eπ ⋅ tan(32°) ⋅ tan²(45° + 32° / 2) = 23.18
The factor Nq considers the load-bearing capacity due to the self-weight of the soil.
Nc = (Nq - 1) ⋅ cot(φ‘d ) = (23.18 kN - 1) ⋅ cot(32°) = 35.49
The factor Nc takes into account the load-bearing capacity due to the cohesion of the soil.
Nγ = 2 ⋅ (Nq - 1) ⋅ tan(φ‘d) = 2 ⋅ (23.18 kN - 1) ⋅ tan(32°) = 27.72 mit δ ≥ φ'd / 2 (rough base)
The Nγ factor considers the bearing capacity due to the shear strength of the soil.
Inclination of Foundation Base
bq = (1 - α ⋅ tan(φ'd))² = (1 - 0)² = 1
bc = bq - (1 - bq) / (Nc ⋅ tan(φ'd)) = 1 - 0 = 1
bγ = bq = 1
In this example, the inclination of the base area α = 0°, and thus has no influence on the bearing resistance.
Shape Coefficients for Rectangular Cross-Sections
The formulas for other cross-sections can be found in Eurocode 1997‑1, D.4.
sq = 1 + B' / L' ⋅ sin(φ’d) = 1 + 1.569 m / 2.50 m ⋅ sin(32°) = 1.333
sc = (sq ⋅ Nq - 1) / (Nq - 1) = (1,333 ⋅ 23,18 - 1) / (23,18 - 1) = 1,348
sγ = 1 - 0.3 ⋅ B' / L' = 1 - 0.3 ⋅ 1.569 m / 2.50 m = 0.812
Slope Coefficients
m = (2 + L' / B') / (1 + L' / B') ⋅ cos²(ω) + (2 + B' / L') / (1 + B' / L') ⋅ sin²(ω)
= 0 + (2 + 1.569 m / 2.500 m) / (1 + 1.569 m / 2.500 m) ⋅ sin²(90°) = 1.614
iq = (1 - Hd / (Vd + A' ⋅ c'd ⋅ cot(φ‘d)))m
= (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 15kN/m² ⋅ cot(32°)))1.614 = 0.858
ic = iq - (1 - iq) / (Nc ⋅ tan(φ'd))
= 0.858 - (1 - 0.858) / (35.49 ⋅ tan(32°)) = 0.852
iγ = (1 - Hd / (Vd + A' ⋅ c'd ⋅ cot(φ'd)))m+1
= (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 15kN/m² ⋅ cot(32°)))1.614+1 = 0.781
The slope coefficient depends on the angle ω.
Bearing Resistance
Influence of foundation depth (the soil adjacent to the foundation and additional loads):
σR,q = q'd ⋅ Nq ⋅ bq ⋅ sq ⋅ iq = 20 kN/m² ⋅ 23.18 ⋅ 1 ⋅ 1.333 ⋅ 0.858 = 530.14 kN/m² with q'd = γ1d ⋅ D
Influence of cohesion:
σR,c = c'd ⋅ Nc ⋅ bc ⋅ sc ⋅ ic = 15 kN/m² ⋅ 35.49 ⋅ 1 ⋅ 1.348 ⋅ 0.852 = 611.11 kN/m²
Influence of foundation width (the soil under the foundation):
σR,γ = 0.5 ⋅ γ'd ⋅ B' ⋅ Nγ ⋅ bγ ⋅ sγ ⋅ iγ = 0.5 ⋅ 20 kN/m³ ⋅ 1.569 m ⋅ 27.72 ⋅ 1 ⋅ 0.812 ⋅ 0.781 = 275.57 kN/m² with γ'd = γ2d
Allowable soil pressure:
σR,k = Rk / A' = σs,q + σs,c + σs,γ = 530.14 kN/m² + 611.11 kN/m² + 275.57 kN/m² = 1,416.83 kN/m²
σR,d = σs,k / γR;v = 1,416.83 kN/m² / 1.00 = 1,416.83 kN/m²
Existing soil pressure:
σE,d = Vd / A' = 3,060.94 kN / 3.922 m² = 780.40 kN/m²
Design ratio
η1 = σE,d / σR,d = 780.40 kN/m² / 1,416.83 kN/m² = 0.551 ≤ 1
Approach 1 (Combination 1-2) According to EN 1997-1, 2.4.7.3.4.2
Calculation of Ground Failure Resistance
Eccentricity ex of Effective Vertical Load in x-Direction
Vz,+add,d = 1.00 ⋅ 1,156.25 kN + 1.30 ⋅ 1,000 kN = 2,456.25 kN
HQ,x,d = 1.30 ⋅ 190 kN = 247 kN
My,+add,d = (1.00 m + 4.00 m) ⋅ 247 kN = 1,235 kNm
ex = -1,235 kNm / 2,456.25 kN = -0.503 m
Effective Foundation Length, Width, and Base
Effective length: L' = max(2.500 m; 2.500 m - 2 ⋅ 0.503 m) = 2.500 m
Effective width: B' = min(2.500 m; 2.500 m - 2 ⋅ 0.503 m) = 1.494 m
Effective area: A' = 2.500 m ⋅ 1.494 m = 3.736 m²
Soil Parameters to Use
Friction angle: φ'd = arctan(tan(32°)/1.25) = 26.56°
Shear parameter for cohesion: c'd = 15 kN/m²/ 1.25 = 12 kN/m²
Bulk density: γ1d = γ2d = 20 kN/m³ / 1.00 = 20 kN/m³
Bearing Capacity Coefficients
Nq = eπ ⋅ tan(26.56°) ⋅ tan²(45° + 26.56° / 2) = 12.59
Nc = (12.59 kN - 1) ⋅ cot(26.56°) = 23.18
Nγ = 2 ⋅ (12.59 kN - 1) ⋅ tan(26.56°) = 11.59 with δ ≥ φ'd / 2 (rough base)
Inclination of Foundation Base
bq = bc = bγ = 1 since α = 0°
Shape Coefficients for Rectangular Cross-Sections
sq = 1 + 1.494 m / 2.500 m ⋅ sin(26.56°) = 1.267
sc = (1,267 ⋅ 12,59-1) / (12,59 - 1) = 1,290
sγ = 1 - 0.3 ⋅ 1.494 m / 2.500 m = 0.821
Slope Coefficients
m = 0 + (2 + 1.494 m / 2.500 m) / (1 + 1.494 m / 2.500 m) ⋅ sin²(90°) = 1.626
iq = (1 - 247 kN / (2,456.25 kN + 3.736 m² ⋅ 12kN/m² ⋅ cot(26.56°)))1.626 = 0.847
ic = 0.847 - (1 - 0.847) / (12.59 ⋅ tan(26.56°)) = 0.834
iγ = (1 - 247 kN / (2,456.25 kN + 3.736 m² ⋅ 12kN/m² ⋅ cot(26.56°)))1.626 + 1 = 0.765
Bearing Resistance
Influence of foundation depth (the soil adjacent to the foundation and additional loads):
σR,q = 20 kN/m² ⋅ 12.59 ⋅ 1 ⋅ 1.267 ⋅ 0.847 = 270.26 kN/m² with q'd = γ1d ⋅ D
Influence of cohesion:
σR,c = 12 kN/m² ⋅ 23.18 ⋅ 1 ⋅ 1.1290 ⋅ 0.834 = 299.31 kN/m²
Influence of foundation width (the soil under the foundation):
σR,γ = 0.5 ⋅ 20 kN/m³ ⋅ 1.494 m ⋅ 11.59 ⋅ 1 ⋅ 0.821 ⋅ 0.765 = 108.68 kN/m² with γ'd = γ2d
Allowable soil pressure:
σR,k = σR,d = 270.26 kN/m² + 299.31 kN/m² + 108.68 kN/m² = 678.25 kN/m²
Existing soil pressure:
σE,d = 2,456.25 kN / 3.736 m² = 657.45 kN/m²
Design ratio
η2 = 657.45 kN/m² / 678.25 kN/m² = 0.969 ≤ 1
Design Approach 1
η = max(η1; η2) = max(0.551; 0.969) = 0.969 ≤ 1
Approach 2 According to EN 1997-1, 2.4.7.3.4.2
In this design approach, a set of partial safety factors A1, M1, and R2 is used, with A1 (γG = 1.35; γQ = 1.5) increasing the unfavorable actions on the foundation, and M1 (γ'φ = γ 'c = γγ = 1.00) not reducing the soil parameters, but with R2 (γR;v = γR;h = 1.40) reducing the resistances.
Calculation of Ground Failure Resistance
Eccentricity ex of Effective Vertical Load in x-Direction
Vz,+add,d = 1.35 ⋅ 1,156.25 kN + 1.50 ⋅ 1,000 kN = 3,060.94 kN
HQ,x,d = 1.50 ⋅ 190 kN = 285 kN
My,+add,d = (1.00 m + 4.00 m) ⋅ 285 kN = 1,425 kNm
ex = -1,425 kNm / 3,060.94 kN = -0.466 m
Effective Foundation Length, Width, and Base
Effective length: L' = max(2.500 m; 2.500 m - 2 ⋅ 0.466 m) = 2.500 m
Effective width: B' = min(2.500 m; 2.500 m - 2 ⋅ 0.466 m) = 1.569 m
Effective area: A' = 2.500 m ⋅ 1.569 m = 3.922 m²
Soil Parameters to Use
Friction angle: φ'd = 32°
Shear parameter for cohesion: c'd = 15 kN/m²
Bulk density: γ1d = γ2d = 20 kN/m³
Bearing Capacity Coefficients
Nq = eπ ⋅ tan(32°) ⋅ tan²(45° + 32° / 2) = 23.18
Nc = (23.18 kN - 1) ⋅ cot(32°) = 35.49
Nγ = 2 ⋅ (23.18 kN - 1) ⋅ tan(32°) = 27.72 with δ ≥ φ‘d / 2 (rough base)
Inclination of Foundation Base
bq = bc = bγ = 1 since α = 0°
Shape Coefficients for Rectangular Cross-Sections
sq = 1 + 1.569 m / 2.500 m ⋅ sin(32°) = 1.333
sc = (1,333 ⋅ 23,18-1) / (23,18-1) = 1,348
sγ = 1 - 0.3 ⋅ 1.569 m / 2.500 m = 0.812
Slope Coefficients
m = 0 + (2 + 1.569 m / 2.500 m) / (1 + 1.569 m / 2.500 m) ⋅ sin²(90°) = 1.614
iq = (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 12kN/m² ⋅ cot(32°) ))1.614 = 0.858
ic = 0.858 - (1 - 0.858) / (23.18 ⋅ tan(32°)) = 0.852
iγ = (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 12kN/m² ⋅ cot(32°)))1.614 + 1 = 0.781
Bearing Resistance
Influence of foundation depth (the soil adjacent to the foundation and additional loads):
σR,q = 20 kN/m² ⋅ 23.18 ⋅ 1 ⋅ 1.333 ⋅ 0.858 = 530.14 kN/m² with q‘d = γ1d ⋅ D
Influence of cohesion:
σR,c = 15 kN/m² ⋅ 35.49 ⋅ 1 ⋅ 1.1290 ⋅ 0.852 = 611.11 kN/m²
Influence of foundation width (the soil under the foundation):
σR,γ = 0.5 ⋅ 20 kN/m³ ⋅ 1.569 m ⋅ 27.72 ⋅ 1 ⋅ 0.812 ⋅ 0.781 = 275.57 kN/m² with γ‘d = γ2d
Allowable soil pressure:
σR,k = σR,d = 530.14 kN/m² + 611.11 kN/m² + 275.57 kN/m² = 1,416.83 kN/m²
σR,d = 1,416.83 kN/m² / 1.40 = 1,012.02 kN/m²
Existing soil pressure:
σE,d = 3,060.94 kN / 3.922 m² = 780.40 kN/m²
Design Approach 2
η = 780.40 kN/m² / 1,012.02 kN/m² = 0.771 ≤ 1
Approach 2* According to EN 1997-1, 2.4.7.3.4.2
In this design approach, a set of partial safety factors A1, M1, and R2 is used, with A1 (γG = 1.35; γQ = 1.5) increasing the unfavorable actions on the foundation, and M1 (γ'φ = γ 'c = γγ = 1.00) not reducing the soil parameters, but with R2 (γR;v = γR;h = 1.40) reducing the resistances.
The eccentricity of the resultant and the inclination factors are not determined with the design values of actions as in Approach 2, but with characteristic actions. In most cases, this leads to smaller eccentricities and thus to a larger effective area, whereby the allowable soil pressure is higher than in Approach 2.
Calculation of Ground Failure Resistance
Eccentricity ex of Effective Vertical Load in x-Direction
In contrast to the other approaches, this approach uses the characteristic values of the vertical load with additional foundation loads Vz,+add,k as well as the characteristic value of the resulting design bending moment in the foundation base center My,+add,k to determine the existing eccentricity.
Vz,+add,k = 1,156.25 kN + 1,000 kN = 2,156.25 kN
HQ,x,k = 1.50 ⋅ 190 kN = 190 kN
My,+add,k = (1.00 m + 4.00 m) ⋅ 190 kN = 950 kNm
ex = -950 kNm / 2,156.25 kN = -0.441 m
Effective Foundation Length, Width, and Base
Effective length: L' = max(2.500 m; 2.500 m - 2 ⋅ 0.441 m) = 2.500 m
Effective width: B' = min(2.500 m; 2.500 m - 2 ⋅ 0.441 m) = 1.619 m
Effective area: A' = 2.500 m ⋅ 1.619 m = 4.047 m²
Soil Parameters to Use
Friction angle: φ'd = 32°
Shear parameter for cohesion: c'd = 15 kN/m²
Bulk density: γ1d = γ2d = 20 kN/m³
Bearing Capacity Coefficients
Nq = eπ ⋅ tan(32°) ⋅ tan²(45° + 32° / 2) = 23.18
Nc = (23.18 kN - 1) ⋅ cot(32°) = 35.49
Nγ = 2 ⋅ (23.18 kN - 1) ⋅ tan(32°) = 27.72 with δ ≥ φ‘d / 2 (rough base)
Inclination of Foundation Base
bq = bc = bγ = 1 since α = 0°
Shape Coefficients for Rectangular Cross-Sections
sq = 1 + 1.619 m / 2.500 m ⋅ sin(32°) = 1.343
sc = (1,343 ⋅ 23,18 - 1) / (23,18 - 1) = 1,359
sγ = 1 - 0.3 ⋅ 1.619 m / 2.500 m = 0.806
Slope Coefficients
m = (2 + 1.619 m / 2.500 m) / (1 + 1.619 m / 2.500 m) ⋅ sin²(90°) = 1.607
iq = (1 - 190 kN / (2,156.25 kN + 4.047 m² ⋅ 12kN/m² ⋅ cot(32°)))1.607 = 0.868
ic = 0.868 - (1 - 0.868) / (23.18 ⋅ tan(32°)) = 0.862
iγ = (1 - 190 kN / (2,156.25 kN + 4.047 m² ⋅ 12kN/m² ⋅ cot(32°)))1.607 + 1 = 0.795
Bearing Resistance
Influence of foundation depth (the soil adjacent to the foundation and additional loads):
σR,q = 20 kN/m² ⋅ 23.18 ⋅ 1 ⋅ 1.343 ⋅ 0.868 = 540.42 kN/m² with q'd = γ1d ⋅ D
Influence of cohesion:
σR,c = 15 kN/m² ⋅ 35.49 ⋅ 1 ⋅ 1.348 ⋅ 0.862 = 623.50 kN/m²
Influence of foundation width (the soil under the foundation):
σR,γ = 0.5 ⋅ 20 kN/m³ ⋅ 1.619 m ⋅ 27.72 ⋅ 1 ⋅ 0.806 ⋅ 0.795 = 287.33 kN/m² with γ'd = γ2d
Allowable soil pressure:
σR,k = 540.42 kN/m² + 623.50 kN/m² + 287.33 kN/m² = 1,451.25 kN/m²
σR,d = 1,451.25 kN/m² / 1.40 =1,036.61 kN/m²
Existing soil pressure:
Vz,+add,d = 1.35 ⋅ 1,156.25 kN + 1.50 ⋅ 1,000 kN = 3,060.94 kN
σE,d = 3,060.94 kN / 4.047 m² = 756.33 kN/m²
Design Approach 2*
η = 756.33 kN/m² / 1,036.61 kN/m² = 0.730 ≤ 1
Approach 3 According to EN 1997-1, 2.4.7.3.4.2
In this design approach, a set of partial safety factors A1 and A2, M2, and R3 is used. For the actions from the structure, the partial safety factors from the data set A1 (γG = 1.35; γQ = 1.50) are used, while the geometric actions should be increased with the data set A2 (γG = 1.00; γQ = 1.30). In addition, the soil properties are reduced by M2 (γ'φ = γ'c = 1.25; γγ=1.00). R3 (γR;v = γR;h = 1.00) does not reduce the resistances.
Calculation of Ground Failure Resistance
Eccentricity ex of Effective Vertical Load in x-Direction
Vz,+add,d = 1.35 ⋅ 1,156.25 kN + 1.50 ⋅ 1,000 kN = 3,060.94 kN
HQ,x,d = 1.50 ⋅ 190 kN = 285 kN
My,+add = (1.00 m + 4.00 m) ⋅ 285 kN = 1,425 kNm
ex = -1,425 kNm / 3,060.94 kN = -0.466 m
Effective Foundation Length, Width, and Base
Effective length: L' = max(2.500 m; 2.500 m - 2 ⋅ 0.466 m) = 2.500 m
Effective width: B' = min(2.500 m; 2.500 m - 2 ⋅ 0.466 m) = 1.569 m
Effective area: A' = 2.500 m ⋅ 1.569 m = 3.922 m²
Soil Parameters to Use
Friction angle: φ'd = arctan(tan(32°) / 1.25) = 26.56°
Shear parameter for cohesion: c'd = 15 kN/m²/ 1.25 = 12 kN/m²
Bulk density: γ1d = γ2d = 20 kN/m³
Bearing Capacity Coefficients
Nq = eπ ⋅ tan(26.56°) ⋅ tan²(45° + 26.56° / 2) = 12.59
Nc = (12.59 kN - 1) ⋅ cot(26.56°) = 23.18
Nγ = 2 ⋅ (12.59 kN - 1) ⋅ tan(26.56°) = 11.59 with δ ≥ φ‘d / 2 (rough base)
Inclination of Foundation Base
bq = bc = bγ = 1 since α = 0°
Shape Coefficients for Rectangular Cross-Sections
sq = 1 + 1.569 m / 2.500 m ⋅ sin(26,56°) = 1.281
sc = (1,281 ⋅ 12,59 - 1) / (12,59 - 1) = 1,305
sγ = 1-0.3 ⋅ 1.569 m / 2.500 m = 0.812
Slope Coefficients
m = (2 + 1.569 m / 2.500 m)/ (1 + 1.569 m / 2.500 m) ⋅ sin²(90°) = 1.614
iq = (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 12kN/m² ⋅ cot(26.56°)))1.614 = 0.858
ic = 0.858 - (1 - 0.858) / (12.59 ⋅ tan(26.56°) ) = 0.846
iγ = (1 - 285 kN / (3,060.94 kN + 3.922 m² ⋅ 12kN/m² ⋅ cot(26.56°)))1.614 + 1 = 0.781
Bearing Resistance
Influence of foundation depth (the soil adjacent to the foundation and additional loads):
σR,q = 20 kN/m² ⋅ 12.59 ⋅ 1 ⋅ 1.281 ⋅ 0.858 = 276.70 kN/m² with q'd = γ1d ⋅ D
Influence of cohesion:
σR,c = 12 kN/m² ⋅ 23,18 ⋅ 1 ⋅ 1,305 ⋅ 0,846 = 307,07 kN/m²
Influence of foundation width (the soil under the foundation):
σR,γ = 0.5 ⋅ 20 kN/m³ ⋅ 1.569 m ⋅ 11.59 ⋅ 1 ⋅ 0.812 ⋅ 0.781 = 115.19 kN/m² with γ'd = γ2d
Allowable soil pressure:
σR,k = σR,d = 276.70 kN/m² + 307.07 kN/m² + 115.19 kN/m² = 698.95 kN/m²
Existing soil pressure:
σE,d = 3,060.94 kN / 3.922 m² = 780.40 kN/m²
Design Approach 3
η = 780.40 kN/m² / 698.95 kN/m² = 1.117 ≥ 1
Comparison of Design Checks
The differences in the design process of Approaches 1 (Combination 1-1), 1 (Combination 1-2), 2, 2*, and 3 are mainly in the partial safety factors. The following table clearly shows the effects of the different safety concepts.
Symbol | Unit | Approach | |||||
1-1 | 1-2 | 2 | 2* | 3 | |||
Partial Factors (Actions A) | A | [−] | 1 | 2 | 1 | 1 | 1 (2) 1)A |
γGAAAA | [−] | 1.35 | 1.00 | 1.35 | 1.35 | 1.35 (1.00) | |
γQ | [−] | 1.50 | 1.30 | 1.50 | 1.50 | 1.50 (1.30) | |
Vertical Load in z | VG,z+add,k | kN | 1156.25 | ||||
VQ,z | kN | 1000 | |||||
∑Vz+add,k | kN | 2156.25 | |||||
Vz+add,d | kN | 3060.94 | 2,456.25 | 3060.94 | 3060.94 | 3060.94 | |
Horizontal Load in x | HQ,x,k | kN | 190 | ||||
HQ,x,d | kN | 285 | 247 | 285 | 285 | 285 | |
Loads for Calculation of Resistances | Vz | kN | 3060.94 | 2,456.25 | 3060.94 | 2,156.25 2) | 3060.94 |
Hx | kN | 285 | 247 | 285 | 1902) | 285 | |
Design Moment in Foundation Base | My,x+add | kNm | 1425 | 1235 | 1425 | 950 | 1425 |
Eccentricity in x | ex | m | -0.466 | -0.503 | -0.466 | -0.441 | -0.466 |
Effective Length | L' | m | 2.500 | ||||
Effective Width | B' | m | 1.569 | 1.494 | 1.569 | 1.619 | 1.569 |
Effective Area | A' | m² | 3.922 | 3.736 | 3.922 | 4.047 | 3.922 |
Partial Safety Factors (Material M) | M | [−] | 1 | 2 | 1 | 1 | 2 |
γ‘φ | [−] | 1.00 | 1.25 | 1.00 | 1.00 | 1.25 | |
γ‘c | [−] | 1.00 | 1.25 | 1.00 | 1.00 | 1.25 | |
γγ | [−] | 1.00 | 1.00 | 1.00 | 1.00 | 1.00 | |
Friction Angle | φ'k | ° | 32 | ||||
φ'd | ° | 32 | 26.56 | 32 | 32 | 26.56 | |
Cohesion | c’k | kN/m² | 15 | ||||
c'd | kN/m² | 15 | 12 | 15 | 15 | 12 | |
Specific Weight | γ1,k= γ2,k | kN/m³ | 20 | ||||
γ1,d= γ2,d | kN/m³ | 20 | |||||
Bearing Capacity Coefficient | Nq | [−] | 23.18 | 12.59 | 23.18 | 23.18 | 12.59 |
Nc | [−] | 35.49 | 23.18 | 35.49 | 35.49 | 23.18 | |
Nγ | [−] | 27.72 | 11.59 | 27.72 | 27.72 | 11.59 | |
Shape Coefficient for Rectangular Cross-Sections | sq | [−] | 1.333 | 1.267 | 1.333 | 1.343 | 1.281 |
sc | [−] | 1.348 | 1.290 | 1.348 | 1.359 | 1.305 | |
sγ | [−] | 0.812 | 0.821 | 0.812 | 0.806 | 0.812 | |
m | [−] | 1.614 | 1.626 | 1.614 | 1.607 | 1.614 | |
Slope Coefficients | iq | [−] | 0.858 | 0.847 | 0.858 | 0.868 | 0.858 |
ic | [−] | 0.852 | 0.834 | 0.852 | 0.862 | 0.846 | |
iγ | [−] | 0.781 | 0.765 | 0.781 | 0.795 | 0.781 | |
Stress Foundation Depth | σR,q | kN/m² | 530.14 | 270.26 | 530.14 | 540.42 | 276.70 |
Stress Cohesion | σR,c | kN/m² | 611.11 | 299.31 | 611.11 | 623.50 | 307.07 |
Stress Foundation Depth | σR,γ | kN/m² | 275.57 | 108.68 | 275.57 | 287.33 | 115.19 |
Partial Factors (Resistance R) | R | [−] | 1 | 1 | 2 | 2 | 3 |
γR;v | [−] | 1.00 | 1.00 | 1.40 | 1.40 | 1.00 | |
Allowable Soil Pressure | σR,k | kN/m² | 1,416.83 | 678.25 | 1,416.25 | 1,451.25 | 698.95 |
σR,d | kN/m² | 1,416.83 | 678.25 | 1,012.02 | 1,036.61 | 698.95 | |
Existing Soil Pressure | σE,d | kN/m² | 780.40 | 657.45 | 780.40 | 756.33 | 780.40 |
Design ratio | η | [−] | 0.551 | 0.969 | 0.771 | 0.730 | 1.117 |
0.969 | |||||||
1) In the case of actions from the supporting structure, the partial safety factors from the data set A1 are used, whereas geometric actions have to be increased with the data set A2. | |||||||
2) The characteristic actions are used to determine the resistance in Approach 2*. |
Conclusion
Zusammenfassend lässt sich feststellen, dass die Verfahren aus EN 1997-1 unterschiedliche Sicherheitsniveaus und ökonomische Effizienz bieten.
Approach 1 is characterized by the fact that it requires two combinations with different safety concepts. This allows for a differentiated view of the safety requirements and ensures that the combination with the higher design ratio is governing. Combination 1-1 increases the actions on the foundation, whereas Combination 1-2 reduces the material properties.
Approach 2 and Approach 2* simplify the design compared to Approach 1, because each uses one data set only. This data set increases the actions and reduces the resistances without reducing the soil parameters. When calculating the soil bearing resistance, the position (eccentricity) and the load inclination of the resultant are important input values. Approach 2 uses the design values for this, while Approach 2* works with the characteristic actions, which leads to a greater bearing resistance in Approach 2*.
Approach 3 usually leads to particularly conservative results, because the data set of partial safety factors used here increases the actions and reduces the soil parameters, without reducing the resistances. This approach usually provides the highest level of safety.