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51x

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2024-01-16

Formula 12

\begin{array}{l} E = 2 \cdot \frac{e_{f}}{d_{c}} = 2 \cdot \frac{0.00}{5.00} = 0.00 (5.10) \\ C_{pf} = 0.21 \cdot C_{op} \cdot (1 2 \cdot E ²) \cdot (1 - e^{- 1.5 \cdot (\frac{h_{c}}{d_{c}} - 1)}) = 0.21 \cdot 0.50 \cdot (1 2 \cdot 0.002) \cdot (1 - e^{- 1.5 \cdot (\frac{8.00}{5.00} - 1)}) = 0.06 \geq 0 (5.9) \end{array}

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