项目介绍
如下图所示,设置一个悬臂梁,其左端完全固定,并施加弯矩。 The problem is described by the following set of parameters. Small deformations are considered and the self-weight is neglected in this example. Determine the maximum deflection uz,max.
Material | Elastic-Plastic | 弹性模量 | E | 210000.000 | MPa |
泊松比 | ν | 0.000 | - | ||
剪切模量 | G | 105000.000 | MPa | ||
Plastic Strength | fy | 240.000 | MPa | ||
Geometry | Cantilever | 周长 | L | 2.000 | m |
宽度 | w | 0.005 | m | ||
厚度 | t | 0.005 | m | ||
Load | 弯矩 | M | 6.000 | Nm |
Analytical Solution
The cantilever is loaded by the bending moment M. The quantities of this load are discussed at first. The moment Me when the first yield occurs and the ultimate moment Mp when the structure becomes plastic hinge are calculated as follows:
The bending moment M causes the elastic-plastic state. The cross-section in the elastic-plastic state is divided into the elastic core and the plastic surface, which is described by the parameter zp according to the following diagram.
The elastic-plastic moment Mep in the cross-section has to equal to the bending moment M. The curvature κ results from this equality.
The total deflection of the structure uz,max is calculated using the Mohr's integral.
RFEM Settings
- Modeled in RFEM 5.16 and RRFEM 6.01
- The element size is lFE= 0.020 m
- Geometrically linear analysis is considered
- The number of increments is 5
- Shear stiffness of the members is neglected
结果
Material Model | Analytical Solution | RFEM 5 | RFEM 6 | ||
uz,max [m] | uz,max [m] | Ratio [-] | uz,max [m] | Ratio [-] | |
Orthotropic Plastic 2D | 1.180 | 1.190 | 1.008 | 1.190 | 1.008 |
Isotropic Plastic 2D/3D, Plate | 1.173 | 0.994 | 1.173 | 0.994 | |
一维各向同性塑性 | 1.180 | 1.000 | 1.180 | 1.000 | |
Isotropic Nonlinear Elastic 2D/3D, Plate, Mises | 1.190 | 1.008 | 1.190 | 1.008 | |
Isotropic Nonlinear Elastic 2D/3D, Plate, Tresca | 1.190 | 1.008 | 1.190 | 1.008 | |
一维各向同性塑性 | 1.180 | 1.000 | 1.180 | 1.000 |