Formula 5

\begin{array}{l} ρ = {(\frac{2 \cdot V_{Ed}}{V_{pl, Rd}} - 1)}^{2} = {(\frac{2 \cdot 853.55}{1, 258.41} - 1)}^{2} = 0.127 \\ A_{w} = h_{w} \cdot t_{w} = (59 - 2 \cdot 2.5) \cdot 1.3 = 70.2 cm \\ M_{pl, V, Rd} = (W_{pl, y} - \frac{ρ \cdot A_{w}^{2}}{4 \cdot t_{w}}) \cdot \frac{f_{y}}{γ_{M 0}} = (5, 360 - \frac{0.127 \cdot 70 . 2^{2}}{4 \cdot 1.3}) \cdot \frac{23.5}{1 \cdot 100} = 1, 231.32 kNm \\ M_{Ed} < M_{pl, V, Rd} \to 1, 068.36 < 1, 231.32 kNm \end{array}

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