Formule 5

\begin{array}{l} ρ = {(\frac{2 \cdot V_{Ed}}{V_{pl, Rd}} - 1)}^{2} = {(\frac{2 \cdot 853, 55}{1258, 41} - 1)}^{2} = 0, 127 \\ A_{w} = h_{w} \cdot t_{w} = (59 - 2 \cdot 2, 5) \cdot 1, 3 = 70, 2 cm \\ M_{pl, V, Rd} = (W_{pl, y} - \frac{ρ \cdot A_{w}^{2}}{4 \cdot t_{w}}) \cdot \frac{f_{y}}{γ_{M 0}} = (5360 - \frac{0, 127 \cdot 70, 2^{2}}{4 \cdot 1, 3}) \cdot \frac{23, 5}{1 \cdot 100} = 1231, 32 kNm \\ M_{Ed} < M_{pl, V, Rd} \to 1068, 36 < 1231, 32 kNm \end{array}

Avez-vous des questions ?