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001324

2023-10-05

Applicable Shear Force

Applicable Shear Force – Knowledge Base Article 1816

η = 0.8

F_{s, k} = η \cdot E_{ah, k} \cdot \tan φ_{α}

F_{s, k} = 0.8 \cdot (0.5 \cdot 7.1 kN / m^{2} \cdot 1.5 m) \cdot \tan \frac{2}{3} \cdot 30 ° + 0.5 \cdot (7.1 kN / m^{2} + 20.5 kN / m^{2}) \cdot 5.3 m \cdot \tan \frac{2}{3} \cdot 30 ° + 0.5 \cdot (18.3 kN / m^{2} + 27.9 kN / m^{2}) \cdot 3.2 m \cdot \tan \frac{2}{3} \cdot 32.5 °

F_{s, k} = 46.32 kN / m

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