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2019-11-04

按照 2014 CSA 规范对木结构梁进行设计

使用 RF-TIMBER CSA 模块可以按照 CSA O86-14 对木结构梁进行设计。 准确地计算木结构杆件的抗弯承载力和调整系数对于安全设计具有重要的意义。 下面的文章将按照CSA O86-14规范,使用解析方程在RFEM附加模块RF-TIMBER CSA中验算调整后的弯矩承载力设计值。利用率

木结构梁分析

A simply supported 10-foot-long, nominal 38 mm ⋅ 89 mm Douglas Fir-Larch Structural (DF-L SS) beam with a mid-span point load of 1.250 kips will be designed. The goal of this analysis is to determine the adjusted bending factors and moment resistance of the beam. A long-term load duration is assumed. The loading criteria are simplified for this example. Typical load combinations can be referenced in Sec. 5.2.4 [1]. In Image 01, a diagram of the simple beam with loads and dimensions is shown.

Beam Properties

The cross-section used in this example is a 89 mm ⋅ 184 mm nominal dimension lumber. The actual cross-section property calculations of the sawn timber beam can be viewed below:

  • b = 3.50 in, d = 7.24 in, L = 10 ft
  • Gross cross-section area:
  • 截面模量:
  • Moment of inertia:

The material that will be used for this example is DF-L SS. The material properties are as follows.

  • Reference bending design value: fb = 2,393.12 psi
  • Modulus of elasticity: E = 1,812,970 psi

Beam Modification Factors

For the design of timber members as per the CSA O86-14 standard, modification factors must be applied to the reference bending design value (fb). This will ultimately provide the adjusted bending design value (Fb), as well as the factored bending moment resistance (Mr).

Below, each modification factor is further explained and determined for this example.

KD

The load duration factor accounts for different load periods. Snow, wind, and earthquake loads are considered with KD. This means KD is dependent on the load case. In this case, KD is set to 0.65 as per Table 5.3.2.2 [1], assuming a long-term load duration.

K[THESIS.THESISTITLE]

The wet service factor considers dry or wet service conditions on sawn lumber as well as cross-section dimensions. For this example, we are assuming bending at the extreme fiber and wet service conditions. Based on Table 6.4.2 [1], Ks is equal to 0.84.

KT

The treatment adjustment factor considers wood that has been treated with fire-retardant or other strength-reducing chemicals. This factor is determined from strength and stiffness capacities based on documented time, temperature, and moisture tests. For this factor, Sec. 6.4.3 [1] is referenced. For this example, 0.95 is multiplied by the modulus of elasticity and 0.85 for all other properties when assuming wet service conditions.

KZ

The size factor considers varying sizes of lumber and how the loading is applied to the beam. More info on this factor can be found in Sec. 6.4.5 [1]. For this example, KZ is equal to 1.30 based on dimensions, bending and shear, and Table 6.4.5 [1].

KH

The system factor takes into account sawn lumber members that consists of three or more essentially parallel members. These members cannot be spaced more than 610 mm apart and mutually support the load. This criteria is defined as case 1 in Sec. 6.4.4 [1]. For this example, KH is equal to 1.10 using Table 6.4.4, because we assume it as a bending member and case 1.

KL

The lateral stability factor considers lateral supports provided along the member length which help prevent lateral displacement and rotation. The lateral stability factor (KL) is calculated below.

Factored Specified Strength in Bending (FB)

The factored specified strength in bending (Fb) is determined in the section below. Fb is calculated by multiplying the specified strength for bending (fb) by the following modification factors.

  • KD = 0.65
  • KH = 1.10
  • Ks = 0.84
  • KT = 0.85

We can now calculate Fb by using the following equation from Sec. 6.5.4.1 [1].


Fb = 1,221.71 psi

Lateral Stability Factor, KL

The lateral stability factor (KL) is calculated from Sec. 6.5.4.2 [1]. Before KL can be determined, the slenderness ratio must be calculated. First, the effective length (Le) is found in Table 7.5.6.4.3 [1]. For this beam example, a concentrated load is applied at its center with no intermediate supports. The unsupported length (lu) is taken as 10 ft.

  • Le = 1.61 (lu)
  • Le = 16.10 ft

Then, the slenderness ratio (CB) can be calculated based on Sec. 7.5.6.4.3 [1].

Since the slenderness ratio is greater than 10, Ck should be calculated. Referencing Sec. 6.4.2, KSE is equal to 0.94.

CB is less than Ck, so we can now calculate KL based on Sec. 7.5.6.4 (b) [1].

Beam Design Ratio

The ultimate goal of this example is to obtain the design ratio for this simple beam. This will determine if the member size is adequate under the given load, or if it should be further optimized. Calculating the design ratio requires the factored bending moment resistance (Mr) and factored bending Moment (Mf).

The maximum moment about the x-axis (Mf) is found by the following:

Next, the factored bending moment resistance (Mr) can be calculated from Sec. 6.5.4.1 [1].
Mr = 0.90 ⋅ Fb ⋅ S ⋅ Kz ⋅ KL
Mr = 3.63 kip ⋅ ft

Finally, the design ratio (η) can now be calculated.

Application in RFEM

For timber design as per the CSA O86-14 standard in RFEM, the add-on module RF-TIMBER CSA analyzes and optimizes cross-sections based on loading criteria and member capacity for a single member or set of members. When modeling and designing the beam example above in RF-TIMBER CSA, the results can be compared.

In the General Data table of the RF-TIMBER AWC add-on module, the member, loading conditions, and design methods are selected. The material and cross-sections are defined from RFEM and the load duration is set to long-term. The moisture service condition is set to wet and treatment is set to preservative (incised). The effective length (Le) is determined from Table 7.5.6.4.3 [1]. The module calculations produce a factored bending moment (Mf) of 3.125 kip ⋅ ft and a factored bending moment resistance (Mr) of 3.641 kip ⋅ ft. A design ratio (η) of 0.86 is determined from these values, aligning well with the analytical hand calculations shown above.


作者

Alex 负责北美市场的客户培训、技术支持和持续的程序开发。

链接
参考
  1. CSA O86:14,木结构设计
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