公式 15

\begin{array}{l} C_{b} = 1, 0 (6.3) \\ p_{vb} = C_{b} \cdot p_{vf} (hc) = 1, 0 \cdot 68, 15 = 68, 15 kN / m ² (6.2) \\ h_{tp} = \tan Φ_{r} \cdot \frac{d_{c}}{2} = \tan 36, 00 ° \cdot \frac{5, 00}{2} = 1, 82 m (Bild 6.3) \\ p_{vtp} = γ \cdot h_{tp} = 16, 00 \cdot 1, 82 = 29, 06 kN / m ² (6.15) \\ p_{vho} = γ \cdot z_{v} = 16, 00 \cdot 0, 61 = 9, 69 kN / m ² (5.79) \\ {Δp}_{sq} = p_{vtp} - p_{vho} = 29, 06 - 9, 69 = 19, 37 kN / m ² (6.14) \\ p_{vsq} = p_{vb} {Δp}_{sq} \cdot \frac{2, 0 - \frac{h_{c}}{d_{c}}}{2, 0 - \frac{h_{tp}}{d_{c}}} = 68, 15 19, 37 \cdot \frac{2, 0 - \frac{8, 00}{5, 00}}{2, 0 - \frac{1, 82}{5, 00}} = 72, 89 kN / m ² (6.13) \end{array}

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