Fórmula 6

\begin{array}{l} k_{A} = 0, 1 (base fija del pilar) \\ k_{B} = \frac{\sum (\frac{E \cdot I_{col}}{l_{col}})}{\sum (\frac{α \cdot E \cdot I_{R}}{l_{R}})} \\ k_{B} = \frac{\frac{3.300 kN / {cm}^{2} \cdot 160.000 {cm}^{4}}{3 m} \frac{3.300 kN / {cm}^{2} \cdot 160.000 {cm}^{4}}{1, 5 m}}{\frac{3 \cdot 3.300 kN / {cm}^{2} \cdot 160.000 {cm}^{4}}{3 m}} \\ k_{B} = 1, 0 \\ l_{0} = 3 m \cdot \max \{\begin{cases} \sqrt{1 10 \cdot \frac{0, 1 \cdot 1, 0}{0, 1 1, 0}} = 1, 38 \\ (1 \frac{0, 1}{1 0, 1}) \cdot (1 \frac{1, 0}{1 1, 0}) = 1, 64 \end{cases} \\ l_{0} = 4, 91 m \end{array}

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